Disucss Test Questions - Test:87 QNo:6

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scintillating dev ·2010-09-29 23:25:01

please explain this in details..

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harrys ·2010-09-30 09:58:51

hey we take angle with +ve x-axis for finding slope not w.r.t other lines

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Abhisek ·2010-09-30 10:42:17

Sorry! My mistake.(i deleted my reply!)...
can anyone please post the full question?

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scintillating dev ·2010-10-02 10:46:09

please explain. sry, i didn't get u .

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Abhisek ·2010-10-02 12:15:57

My method was wrong...so i deleted the post......

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harrys ·2010-10-02 12:30:13

find the point of intersection of given lines you will get 2 points of angle bisector one is (4,5) andotheris calculated

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scintillating dev ·2010-10-02 23:35:04

u mean we hav 2 manually test which of the bisectors contain (4,5)??

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Abhisek ·2010-10-03 01:52:48

Apparently that is the only method clicking my mind....Nishant Sir can u help ?

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scintillating dev ·2010-10-03 02:08:24

But that is gonna b 2 lengthy in a comp exm..

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Abhisek ·2010-10-03 02:35:11

Hey try drawing the graph.....does the angle-bisector actually seem to pass through (4,5) ? I doubt it... :-|

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nihal raj ·2010-10-03 04:16:02

..........

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scintillating dev ·2010-10-03 08:12:14

QUESTION IS NOT WRONG. IT'S A TEST QUESTION BY TARGETIIT.

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scintillating dev ·2010-10-03 08:13:06

BUT WHERE IS NISHANT SIR?? WE REALLY NEED HIM!!!!!!!!!![2]

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harrys ·2010-10-03 09:20:47

use the angle formula between two lines tanÑ² = m₁ - m₂ / 1 +m₁m₂ where Ñ² = angle between two lines and value is 45⁰ and m₁ and m₂ are slope two lines you will get the slope of bisector

tan45⁰ = -34 - m1 - 34m

34m - 1 = 34 + m

m = -7
now
(y - 5) = -7(x - 4)

7x+y-33=0

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scintillating dev ·2010-10-03 09:23:13

thanx

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Test:87 QNo:6

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