1please explain this in details..
find the bisector of the lines 3x+4y+7=0 & 4x-3y-2=0 containing point (4,5)
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15 Answers
1hey we take angle with +ve x-axis for finding slope not w.r.t other lines
1Sorry! My mistake.(i deleted my reply!)...
can anyone please post the full question?
1find the point of intersection of given lines you will get 2 points of angle bisector one is (4,5) andotheris calculated
1u mean we hav 2 manually test which of the bisectors contain (4,5)??
1Apparently that is the only method clicking my mind....Nishant Sir can u help ?
1Hey try drawing the graph.....does the angle-bisector actually seem to pass through (4,5) ? I doubt it... :-|
1use the angle formula between two lines tanѲ = m1 - m2 / 1 +m1m2 where Ѳ = angle between two lines and value is 450 and m1 and m2 are slope two lines you will get the slope of bisector
tan450 = -34 - m1 - 34m
34m - 1 = 34 + m
m = -7
now
(y - 5) = -7(x - 4)
7x+y-33=0