R = 10 ohm
in Ac
10 = 150 /√R2 + w2L2
= 150 /√R2 + (2pie 50)2L2
125 = (2pie 50)2L2
L = 35.5 mH
is it correct ...
V = √5/9*150
An electric lamp which runs 100V dc & comsumes 10A current is connected to ac mains at 150V, 50Hz cycles with a choke coil in series. Calculate the inductance and drop of voltage across the choke. Neglect resistance of choke.
dont u think some data is missing?????[7][7]
From DC eqn. R=10 ohm
IN AC: f=50 Hz,VAC=150V
Vrms=150/√2
I=Vrms/Z
ab kya karen??????????????
ya main kuch bhool raha hoon.......[7]
R = 10 ohm
in Ac
10 = 150 /√R2 + w2L2
= 150 /√R2 + (2pie 50)2L2
125 = (2pie 50)2L2
L = 35.5 mH
is it correct ...
V = √5/9*150