262E = -dVdx = -8x
flux through the four surfaces (parallel to E ) are zero
for the other two ,
Δφ = Δ(E.A) = {-8(1/2).1 } - {-8(-1/2).1} = -8 = q/ε0 (Gauss law)
thus q = -8ε0 C
where ε0 =8.85*10-12 SI units
Q : The potential in a region varies as V = 4x2. Find the charge (in C) enclosed by a cube of side 1 m having its center at Origin.
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3 Answers
262
71Shit man. I had marked it, and then what changed my answer! :( fail