Electricity and magnetism - AIEEE PHYSICS power up

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Lokesh Verma ·2009-04-19 20:53:38

I think the answre should be P/2

which does not seem to be an option :(

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palani ............... ·2009-04-19 22:12:07

i think its b

wats d ans?

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msp ·2009-04-19 22:14:31

cute palani how u got b.

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neil.dhruva ·2009-04-19 22:39:46

shouldn't it be D?

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playpower94 ·2009-04-19 23:32:05

ans is D show method and explanation

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kamalendu ghosh ·2009-04-20 06:21:45

isnt I âˆž (1/r²)..that way we get P/2 but......

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neil.dhruva ·2009-04-20 08:21:50

I' = [I cos(a)]/r²

a=45Â°
r=√2

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palani ............... ·2009-04-21 00:09:06

@neil

I' bcomz dimensionally invalid

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21

tapanmast Vora ·2009-04-21 01:43:49

@palani : not really bcoz in da case wer intensity is I i.e. at pt. B

cos(a) = cos(0) = 1

and r = 1

ther4 these two ones are hidden in I' = [I cos(a)]/r² I guess.....

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playpower94 ·2009-04-24 23:23:38

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kamalendu ghosh ·2009-04-24 23:36:06

total flux =Q/Î¾

there fulx thru the circular parts = Q/Î¾ - Ï†₁

thru one circular part =[Q/Î¾ - Ï†₁]/2

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kamalendu ghosh ·2009-04-24 23:44:49

in your lens um ans will be 1

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playpower94 ·2009-04-25 03:00:32

thanks chk more

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-25 03:02:17

20th itz solvd in hcv part 2........

u can chkc......... typin here wud b savd

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-25 03:10:56

B due to circle

u *i *@/2R (2pi)

so u get by this formula

and for|PQ it willb out of d plane n d othr itz into d plane

so nw u can calculate :P

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-25 03:20:03

sorry upar wala magnctic field ke liey hai
k
so aapko area chahiye

itz
area of d sector

so biger sector -smallr sector

area of sector =(@ /360)*(pir^2)

r=radius

aab u can calculate

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