yes ur answer is correct, even i too had the problem in the same question
In the AC network shown in fig., the rms current through the inductor and capacitor are 0.6A and 0.8A respectively. Then the current coming out of the source is
this quest is also from arihant objectives.... plz help me out in this...
Ok what do we mean when we say the "reactance of the circuit" without mentioning whether it is inductive or capacitive.....
-
UP 0 DOWN 0 0 4
4 Answers
take the voltage source be
V=Vosinωt
now we split the circuit into 2 separate circuits one purely capacitive and another purely inductive,
thus, Ic=Iocsin (ωt+θ)
and IL=IoLsin (ωt-θ)
where
|θ|=π/2
thus we can see that the phase difference between the two wave forms of current is π...
and so at every point of time, IL=-Ic
this gives instantaneous current as |IL|-|Ic|
thus peak value of current is |IoL-Ioc|
RMS current is |IL - Ic√2| = |IL√2 - Ic√2| = Ic rms - IL rms