ANGLE OF DIP

IIT JEE 2015 Answers › Electricity and magnetism questions › ANGLE OF DIP

If angle of dip in two perpendicular planes is Î´1 and Î´2 ,then prove that
cot²Î´1+cot²Î´2 =cot²Î´ where Î´ is true angle of dip.

#Physics #Electricity and magnetism

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rocky ·2010-05-11 05:49:58

if the vertical plane in which angle of dip is Î´1 subtends Î±ngle Î± with magnetic meridian ,the other vertical plane in which angle of dip is Î´2 subtends Î±ngle (90-Î±) magnetic meridian ;so

tanÎ´1 =B_vB_hcos Î±

tanÎ´2 =B_vB_hcos(90-Î±)

and hence cot2Î´1+cot2Î´2 =(B_hB_v)²[cos²Î±+sin²Î±]

cot2Î´1+cot2Î´2 =cot2Î´

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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ANGLE OF DIP

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