If angle of dip in two perpendicular planes is δ1 and δ2 ,then prove that
cot2δ1+cot2δ2 =cot2δ where δ is true angle of dip.
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1 Answers
rocky
·2010-05-11 05:49:58
if the vertical plane in which angle of dip is δ1 subtends αngle α with magnetic meridian ,the other vertical plane in which angle of dip is δ2 subtends αngle (90-α) magnetic meridian ;so
tanδ1 =BvBh cos α
tanδ2 =BvBh cos(90-α)
and hence cot2δ1+cot2δ2 =(Bh Bv)2[cos2α+sin2α]
cot2δ1+cot2δ2 =cot2δ