ANOTHER OF DIPLOES....

For finding the electric field at the center of the dipole which formula will u apply Equitorial one or Axial one....????

19 Answers

1
prateek punj ·

might be the case......

till i remember no such approximations where made except considering the charges to be point charges....

33
Abhishek Priyam ·

[3]

electric field is always same KQ/R2

and those formulas are derived by we mortals to help us... so apply the basic ones wherever possible...

62
Lokesh Verma ·

You guys have answered that already

we use approximation in the cases.. in one of them we assume that the distance is much larger than the distance between the charges.. which gets violated when we come to the center of the dipole..

11
Anirudh Narayanan ·

illai, machan. Prateek knows that. what he is asking is........................
Why aren't we getting the same answer if we substitute in the formula for E at an axial and equitorial point?

11
Subash ·

no need for either formula directly find the field at the point

1
moon ·

jst tht observation pt is very far frm the dipole

11
Anirudh Narayanan ·

moon, do you remember any approximations we make while deriving the formula for electric field due to dipole??

1
moon ·

the idea i m getting reading this is only tht if it shd satisfy both axial nd equatorial pt thn we shd be using dipole due to normal..........

11
Anirudh Narayanan ·

@MOON:
this point lies both on the axis and on the equator. So shouldn't it satisfy both the expressions?

1
moon ·

y cn't u use the electric field due to dipole at any normal pt.,.........it considers dipole due at both axial nd equatorial pt.

1
prateek punj ·

hey guys no reply.....

11
Anirudh Narayanan ·

Maybe that's because we made a lot of approximations while driving the formula.

1
prateek punj ·

i agree with u buddy....
but if consider the formula then the center point should satisfy both the formula bacoz it lie on axial as well as equitorial point but the answers from both is different....

11
Anirudh Narayanan ·

Any formula required? Simple kq/a2 will do won't it? Any complications in that?

1
prateek punj ·

guys no one to answer this....

1
prateek punj ·

guys reply please....

1
prateek punj ·

it's alright.....

39
Dr.House ·

yup i mistook sorry

1
prateek punj ·

it is electric field.....
buddy..it is electric field...the direction of electric field due to both the charges will be in same direction.....

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