another simple one

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A non conducting ring of radius r has charge Q. A magnetic field perpendicular to the plane of the ring changes at the rate of dB/dt. The torque experienced by the ring is?

#Physics #Electricity and magnetism

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Pavithra Ramamoorthy ·2009-03-25 06:44:43

0.??????

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Subash ·2009-03-25 06:45:19

i dont have answer so reason yourself

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Subash ·2009-03-25 06:46:18

what is the significance of the ring being non conducting ?

please explain that

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kamalendu ghosh ·2009-03-25 08:08:59

0??

torque=INa*B

A is perpendicular to the ring.....and so is B ..so cross product is0

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prateek punj ·2009-03-25 08:10:53

also it is non conducting so no current flowing no torque....

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Subash ·2009-03-25 09:40:51

answer is zero then? bhaiyya confirm this one i dont have answer

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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another simple one

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