Answer this orally....

Q) A point charge Q is placed at a distance 'a' above a horizontal plate which is infinitely large.
find the flux passing through the horizontal plate?

13 Answers

19
Debotosh.. ·

all the lines of force from the pt charge are intercepted by this plate ..so.........[4]

62
Lokesh Verma ·

have you just missed it?

19
Debotosh.. ·

isn't it q/ε ?????
edited after kicking and slapping myself !

1
mentor_pankaj agarwal ·

nopes..... you are close 2 it.

hint : imagine another infinite plane opposite to the plane mentioned in the question

39
Dr.House ·

q/ε0

19
Debotosh.. ·

yaar ,,,i have been in some sort of very stupid dilemna since the last 2 days ! i know that its q/ξ but see how idiotically i have posted it as q/4∩ξ .....i have made a similar mistake in another question from maths posted by tushar......i am going to kick myself now ! hard ! [16] [16]

1
mentor_pankaj agarwal ·

the answer is q/2ε0

explanation : imagine another infinite plate just opposite to the existing one.
now half of the electric field lines will pass through each plate, hence the
answer is q / 2ε0.

note : there is only a circle of field lines which don't pass from any of the plates , but that
does n't contribute to the flux because of zero area.

19
Debotosh.. ·

oh no .......but all the field lines are intercepted by the plate !!! so how this ?

1
sakshi pandey pandey ·

i think ................its in the same way as v take flux through any one face of cube ..............

62
Lokesh Verma ·

Look at another imaginary plane symmetrically placed above the charge as showin in the figure..

all the flux lines will pass through either of the two surfaces

so the flux through the bottom surface is half the total flux

so it is q/2ε0

23
qwerty ·

sir u didnt wait for others like me to try this one [2]

1
akari ·

we can approach this question with solid angles too ....
the semivertex angle → 90
solid angle →2pi(1-0)→2pi
flux is
k*q*solid angle
q/2e ......... simple :(

62
Lokesh Verma ·

sorry qwerty.. i thought that no one was solving this one..

@dukhiatma.. i like your aim.. to get a wikipedia page :)

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