A 10 m long wire of uniform cross section and 20 ohm resistance is used in potentiometer.
The wire is connected in series with a battery of 5 V along with an external resistance of 480 ohm. If an unknown emf E is balanced at 6 m length of wire..Calculate:
(i)Potential Gradient of potentiometer wire.
(ii)the value of unknown emf.
now
1) what is the significance of the minus sign before Blv ????
2) what is the vector form of this formula..
like e.g.
Fm = Bqvsin@ or q(v x B)
3) the book says E=0 if l or v is parallel to B
if v is parallel E=0 I've understood
but how if l is parallel to B
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4 Answers
Avinav Prakash
·2010-03-01 08:11:30
2)q(v x B)
3)E=BvLsin@.............if @=0...for L..||..to B
den .....E=0
Tapas Gandhi
·2010-03-01 09:38:40
1) EMF induced is opposite to direction of change in flux (Lenz's Law)
2) [ L v B] i.e. L.(vxB)
3) [L v B] = v.(BxL)=0 if B//L
Drik Paul
·2010-03-01 22:00:10