AB and CD are the plates of a parallel plate capacitor, having 2 dielectrics inserted between them as shown, of constants K1 and K2. Separation between the plates is d and edge length a. Find the capacitance
-
UP 0 DOWN 0 0 2
2 Answers
1161Well this is a bit lengthy question, but still you can try. Concept that is required is:
1) If we cut a capacitor parallely and join them in parallel then total capacitance will remain same.
2) We take any capacitor of height dx, that will be the combination of two capacitors in series C1 and C2.
3) Finally we have to do integration.
229And the answer will come out to be ξa2k1k2 d(k1-k2)* ln(k1/k2)
- Akash Anand Good WorkUpvote·0· Reply ·2013-05-29 02:13:33