Condenser A has a capacity of 15 when it is filled with a medium of dielectric constant 15. Another condenser B has a capacity 1 with air between the plates. Both are charged separately by a battery of 100V. After charging, both are connected in parallel without the battery and the dielectric material being removed. The common potential now is
A. 400V
B. 800V
C. 1200V
D. 1600V
A capacitor of capacitance C is initially charged to a potential difference of V volt. Now it is connected to a battery of 2V with opposite polarity. The ratio of heat generated to the final energy stored in the capacitor will be
a. 1.75
b. 2.25
c. 2.5
d. .5
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1 Answers
1161For the first one, you can easily find out total charge(1500+100=1600 C) on two capacitors, and in final case charge will be equally divided(Think why). So answer would be: 800V.
For the second one, Find the total work done by the battery which will be (2V*3CV..think why). Half of that work done will be lost as heat. Final energy you can easily find out with the given data.
