Capacitors-2

VITEEE 2015 Papers › Electricity and magnetism questions › Capacitors-2

#Physics #Electricity and magnetism

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3 Answers

101

Anurag Roy ·2013-02-26 08:34:29

q_a=ab/(c(b-a)+ab)=-q_b?
q_c=q-q_a?

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1133

Sourish Ghosh ·2013-06-05 06:28:57

Outer surface of a:
qabab+bc-ac

Inner surface of b:
-qabab+bc-ac

Outer surface of b:
qc(a-b)ab+bc-ca

Surface of c:
qc(b-a)ab+bc-ca

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Akash Anand Check the third part, I guess you have made some mistakes there..remaining three are correct.
Upvote·0· Reply ·2013-06-06 02:52:56
Akash Anand Sourish ..correct your answer and try to provide a crisp solution.
Upvote·0· Reply ·2013-06-12 02:10:37
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865

Soumyadeep Basu ·2013-06-12 03:31:46

Inner surface of a: 0
Outer surface of a: qab/(ab+bc-ca)

Inner surface of b: -qab/(ab+bc-ca)
Outer surface of b: 0

Inner surface of c: 0
Outer surface of c: qc(b-a)/(ab+bc-ca).

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Akash Anand Excellent work
Upvote·0· Reply ·2013-06-12 05:02:50
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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω