yep im sorry i forgot to multiply by 2 .......in #2(now edited ) .....
see we need to transport a charge of 5*12*2 thru a pd of 12 .....
but pot. engy of system rem. same ...........
1440 micro J or 1.440 mJ
a 5uF capacitor is charged to 12v . the +ve plate of the capacitor is now connected to the -ve terminal of the battery and vice versa. calculate the heat developed in the connecting wires
yep im sorry i forgot to multiply by 2 .......in #2(now edited ) .....
see we need to transport a charge of 5*12*2 thru a pd of 12 .....
but pot. engy of system rem. same ...........
1440 micro J or 1.440 mJ