A solid spherical region having spherical cavity(concentric) whose diameter R is equal to radius of spherical region ,has a total charge Q.Find electric potential at point at distance x from centre .
1see, it will depend on the position of 'x'.
case 1: if x < = R/2
E.4Πx2 = q/ε0
here, q=0.
so, potential (V=Ed) in this region = 0.
case 2 : if R/2 <x< R
q = find the charge containd 'within' the radius x.
then apply gauss law, find E.
then, V= Ex.
case 3 : if x> R
q= Q.
then similar steps as in case 2.
3if it is a conductor
then there will be electric field only x≥R
E4∩x2=Q/ε0
E=-dV/dx
1hmm... point ....
tx sankara..
i actually dunno y ... din think abt it only ...
