chalte chalte capacitance

we know that for a spherical drop

C is directly proportional to R (radius)

so here if we let radius of each small drop be `r` , then we have that radius of the bigger drop would be 4r.(equating the volumes of the both)

so we have that the capacitance of the bigger drop would be 4C.

C of a spherical capacitance = 4Πε₀R , R=radius of sphere
Now, 1μF = 4Πε₀R
==> R = 1μF/4Πε₀

now radius of the new sphere will be 4 times the individual spheres
[let the radius be r. then 4/3*Î *r³ = 64*4/3*Î *R³ giving r'=4R]

So, the new capacitance will be C = 4Πε₀r = 4Πε₀*4R
= 4μF