3when connected by wire they become equipotentional ....[hope it helps]
try it if u dont get it ill post detailed soln.
a charged sphere A of radius r is placed concentrically inside a conducting spherical shell(B) of radius R (R>r). A charge Q is given to A and then A and B are joined by a metal wire the charge flowing from A to B will be
a.QR/(R+r)
b.Qr/(R-r)
c.Q
d.zero
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4 Answers
3
1if they are equipotential then the charge must not flow as the potential difference is zero but the answer is Q .!?!!!
106Initially there is PD so charges will flow.
What iitimcomin is trying to say is that finally potential of both will become same.
3ull get the net charge flowing out to be Q!!!!!!!!!!!!!
let the new charges on the inner and outer sphere/shell be q1,q2
frm conservation of charge
q1+q2=Q
kq1/r + kq2/R = k(q1+q2)/R
or
q1/r = q1/R
this equation has 2 soln.
r = R :P obiusly rong soln. as R>r
or
q1 = 0 !!!!!!!!!!!!!!!!!!!!
this is a lovely thing i noticed frm ur problem ....................all the charge flows to the outer sphere!!!!!!!!!!!!!!
q2 = Q .......
ur answer shud be Q ......