106Initially there is PD so charges will flow.
What iitimcomin is trying to say is that finally potential of both will become same.
a charged sphere A of radius r is placed concentrically inside a conducting spherical shell(B) of radius R (R>r). A charge Q is given to A and then A and B are joined by a metal wire the charge flowing from A to B will be
a.QR/(R+r)
b.Qr/(R-r)
c.Q
d.zero
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4 Answers
3when connected by wire they become equipotentional ....[hope it helps]
try it if u dont get it ill post detailed soln.
1if they are equipotential then the charge must not flow as the potential difference is zero but the answer is Q .!?!!!
1063ull get the net charge flowing out to be Q!!!!!!!!!!!!!
let the new charges on the inner and outer sphere/shell be q1,q2
frm conservation of charge
q1+q2=Q
kq1/r + kq2/R = k(q1+q2)/R
or
q1/r = q1/R
this equation has 2 soln.
r = R :P obiusly rong soln. as R>r
or
q1 = 0 !!!!!!!!!!!!!!!!!!!!
this is a lovely thing i noticed frm ur problem ....................all the charge flows to the outer sphere!!!!!!!!!!!!!!
q2 = Q .......
ur answer shud be Q ......