2v0(qB0d-mv0mv0) i + vo[8mdqvoBo - 3m2vo2d2 - 4q2d2Bo22mvoqBo] j
vx = v0 - 3qB0d2mvy = √(v02 - vx2)
Yes,got itVx=(V0-3qB0d2m)Vy=√(V02-Vx2)
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