Current Electricity-10

4 Answers

229
Dwijaraj Paul Chowdhury ·

For each bulb....power =v2/r
:. r= v2/p
= 220*220/100 =484
Equivalent resistance(R) =4r/3
:.POWER = V2/R
=( 220*220*3) / (4*484)
= 75 watts

229
Dwijaraj Paul Chowdhury ·

A)__75watts

1
Subhradeep Patra ·

D> 400/3 watts?

535
Aditya Agarwal ·

sir the solution?

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