Doubbt

Take a pen torch cell and then connect with ends with copper wire after a long time the copper wire will burns.This will happens in this case also.

@philip..
whatever I wrote in post#20 has been approved by Kaymant Sir.. [1]

Okk..so final ans is

a) If we take wires to be ideal...then current flows through conducting wire only.....

b)if we dont take it ideal...then initially current is through conducting wire..and after some time it melts away..so that ..current is in bot hthe loops

so no current in top loop and current of 10A in lower loop?
and will the current pass through conducting wire or through resistance??
or both ?

So what? There is an electric field inside the wire which is created by the battery. That will make the current flow. I understand that you are under the impression that the wire is at the same potential throughout. But that is not correct. It is the purpose of the battery to create a constant potential difference between its terminals.

but why will current flow in lower loop ???its shorted naa ???

Ideally speaking the diagrams in #4 are not equivalent. For the original problem, the battery of course works. However, there is no current in the upper loop containing the two resistances. But there is a current in the lower loop formed by the battery and the wire circumventing the lonely resistance. This current is limited by the internal resistance of the battery itself.

all current travels through the wire with parell(r=0), it will get short circuited

lekin pahle tumko resistance less wire dhundna padega

he he

ghar me circuit jod kar dekh lo.. :P

lekin pahle tumko resistance less wire dhundna padega.. :D

sir final ans to bata do..........[2]

so what actually will happen to battery....................will it work or not????

whatever i did in post #4..........is it correct?????????????????

my first choice too was short circuit but then another thought coming to my mind is that ::

am i correct????