Doubt in RC CIRCUIT

i have a doubt which is A and which is B for the first one!!

assuming the left one is A and right one is B
for second part the answer i am getting are 3mA, 2mA and 5mA.

assuming right one to be A and left one B
for second part i am getting answer 3mA, 1mA and 4mA.

so i think the polarity of the 10V cell is given in opposite direction; to be resonating (:P) with the answer the 10V battery must have been connected in opposite sense and the left point should be A and right one B.

else answer given is apparently wrong!!

for Q2))

leave out the upper resistance R...it will draw a constant current of E/R

but in lower loop, let after time t, charge on each capacitor be q and current throught resistor be i .

then, E=q/C₁+iR+q/C₂=q/C+iR...........1/C=1/C₁+1/C₂.

doing this we get same expression as the circuit with one capacitance and 1 resistance.

thus, the equation comes to be q=CE(1-e^-tRC)

time constant=RC=RC₁C₂C₁+C₂.

yeah
!!!