easy.......eq resistance.

where is the wheatstone's bridge?

no . that's not right.

only the Resistances with 2 ohms are removable. so effective R = 7/3 ohms.

its not that much easy also..........

coming with diag . one mo.

ys.........a bit mistake

Circuit is symmetrical about the two 2 Ω resistances........ So same amount of current will enter both branches.......so 2 ohm resistors can be neglected. this gives us an equvalent resistance of 7/3 ohms.

P.S:
IT IS MY REQUEST THAT THIS POST NOT BE PINKED

isn't the circuit symmetrical about the other side also?.............

but we need to calculate eq resistance b/w A and B .........so we have to find symmetry about a line which is perpendicular bisector to imaginary line joining AB

ok