1E.S = k/r^5 +k`/r^3 * ( 4*Î *r^2)
Q1
A solid sphere has a very small cavity at its center (volume of cavity→0).This cavity contains a source of electric field which varies as
E(x) = kx5 + k'x3 (where 'x' = radial distance from the center & k,k' are positive constants)
Assuming the sphere as a normal complete solid sphere(i.e. neglecting the empty volume caused by cavity) ,find the electric flux through the sphere.
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4 Answers
1@redion
electric field is not constant
\phi _{E} = \oint_. E.dS
1Integrate the dot product of electric field and area with limits 0 to R
1@pritishmasti the field is radially symmetrical and @ swordfish plz. explain how can we integrate the flux like this , this is not a an integral but a surface integral, u've got to sum up the contributions of the flux at the surface only, if u're integrating the flux like this u're actually counting the same flux over and over again, electric flux is surface integral of E.dS