26Sir it is a question of the non-conservative electric field which is formed in the ring. I just was able to understand this much about the question. The main thing that is confusing me is the oscillation part of the ring. We read that in a metal rod due to movement in a magnetic field an induced non-conservative electric field is formed. But given that it is a ring I am unable to get hold of the concept of the formation of an electric field as the net current in the ring would be zero just as in case of a square loop moving in a magnetic field because of internal cancellation of the emfs so formed. How is it nonzero( answer is given nonzero ) then ?
Akash Anand In the previous case when the square loop was moving ..in that case magnetic field was constant. If it would be a changing magnetic field then there must be a current in the circuit as well.- Akash Anand Hope now you got the point ..still got some confusion then you may contact after the class.
