Qleft= -325μC
Qmiddle= -230μC
Qright= 95μC
Dwijaraj Paul Chowdhury Sorry I made some mistakes
Akash Anand Wrong answer..keep trying
305 μC on the capacitor in the left, 190 μC on the capacitor in the middle and 115 μC on the capacitor in the right???
Qleft= -325μC
Qmiddle= -230μC
Qright= 95μC
115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
Qleft= 190 μC
Qmiddle= 520 μC
Qright= -330 μC
Qleft=305μC
Qmiddle=210μC
Qright=115μC
Correct Answer is:
Charge on 2μF capacitor(left) is: 35 μC
Charge on 4μF capacitor is: 10 μC
Charge on 2μF capacitor(right) is: 25 μC
There is a correction in the question, please check it again, it should be 20V in place of 200V
For capacitor on the left,
The charge is flowing in the same direction
V=15(from 20v)+ 2.5(from 10v) = 17.5V
Q= 17.5*2 = 35μF
For capacitor in the middle,
The charge is flowing in opposite direction
V=5(from 20v)- 2.5(from 10v) = 2.5V
Q=2.5*4 = 10μF
For capacitor on the right,
Again the charge is flowing in the same direction
V=5(from 20v) + 7.5(from 10v) = 12.5V
Q=12.5*2 = 25μF
@Akash sir, if i use the initial data, is then my answers correct? :P Everyone had done that same thing in their first attempt :P