66305 μC on the capacitor in the left, 190 μC on the capacitor in the middle and 115 μC on the capacitor in the right???
Akash Anand Wrong answer ..keep trying.Upvote·0· Reply ·2013-06-10 23:51:31
11 Answers
66
229Qleft= -325μC
Qmiddle= -230μC
Qright= 95μC
- Dwijaraj Paul Chowdhury Sorry I made some mistakes
- Akash Anand Wrong answer..keep trying
31115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
- Akash Anand Wrong answer..keep trying.
31115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
- Akash Anand Wrong answer..keep trying.
229Qleft= 190 μC
Qmiddle= 520 μC
Qright= -330 μC
- Akash Anand Again wrong answer...try to give me the solution then I will find the mistakes.
- Dwijaraj Paul Chowdhury I used kirchoffs laws....i aimed the charge flowing through the left and right capacitors as q1 and q2 respectively and in the middle charge flowing will be q1-q2
- Dwijaraj Paul Chowdhury That should be read 'assumed' ^
150Qleft=305μC
Qmiddle=210μC
Qright=115μC
- Shreya Sharma Sorry
Qleft= 295μC
Qmiddle= -210μC
Qright= 85μC
- Akash Anand Wrong again...
1161Correct Answer is:
Charge on 2μF capacitor(left) is: 35 μC
Charge on 4μF capacitor is: 10 μC
Charge on 2μF capacitor(right) is: 25 μC
- Akash Anand Now try to solve the question.
1161There is a correction in the question, please check it again, it should be 20V in place of 200V
150For capacitor on the left,
The charge is flowing in the same direction
V=15(from 20v)+ 2.5(from 10v) = 17.5V
Q= 17.5*2 = 35μF
For capacitor in the middle,
The charge is flowing in opposite direction
V=5(from 20v)- 2.5(from 10v) = 2.5V
Q=2.5*4 = 10μF
For capacitor on the right,
Again the charge is flowing in the same direction
V=5(from 20v) + 7.5(from 10v) = 12.5V
Q=12.5*2 = 25μF
- Akash Anand Excellent Work ..keep it up
66@Akash sir, if i use the initial data, is then my answers correct? :P Everyone had done that same thing in their first attempt :P
- Akash Anand Yeah ..may be. Since I did not solve the question so I can't comment. BUt if this time you are getting the right answer then I am sure at first attempt you were correct.
- Sourup Nag hmm.. got it this time