39What about the second one? We somehow have to use V0 but I'm not getting..
1.A small block of mass m is kept a smooth inclined plane of angle 30° between two charged vertical sheet.Electric field E exists between the verticle sides of the walls of the elevator.The charge on the block is +q.Elevator accelerates with acc. a upward. The time taken by block to rech the bottom of incline is??
Ans.2*√2h/[g-qe/m)√3]
2.If Vo be the potential at the orgin in an electric field E =Exi+Eyj,then potential at point P(x,y) is----??
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UP 0 DOWN 0 0 11
11 Answers
39Disclaimer : I am only an amateur in physics.
We have to find the acceleration of the block by force equations.
It is the horizontal direction wrt the block we are concerned with.
qEcos30° + mgsin30° = macos30°
=> √3qE2 + mg2 = √3ma2
=> √3qE + mg = √3ma
=> a = qEm + g√3
Now we have the height h from which the block begins from rest, and the acceleration of the block.
h = ut + 0.5at²
=> h = 0 + (qE2m + g2√3) * t²
Looks like my answer's coming wrong..you didn't specify which side the positive plate is on and which side the negative one is..
39lol ab khud karo....tabhi qE + mg aa raha hai aur minus nahi :P
39
39I did that but not getting...got an integration and I'm getting something like : V = -Exx - Eyy...we have to use V0 too isn't it?
39Yes I'm not getting the V0. Evidently some mistake I've made.
39Yes this is it! We had to take potential difference..lol.
The upper limit is (x, y, 0) btw...but it's alright.
And the lower limit is (0,0,0).