arre yaar..........tum log hc verma ke peeche pade ho........mere method mein galti batao.....
if u know this it is easy but if u dont know, its worth knowing....
Q) a spherical ball of radius R is uniformly charged with charge density Ï .determine the electrostatic energy of the sphere.
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haan priyam.[4][4]..........mera bhi aa gaya tha raat ko[3][3]...............main to mathie ko chaalenge kar raha thaa ki meri galti nikale[6]..............mujhe mere answers par pura bharosa hai .....hamesha......[1]
are eureka...
u are right... apne par bharosa rakh...
put Ï=Q/(4piR3/3)
aa jaega... kyunki method sahi hai...
and mathiee.. u asked in terms of Ï so should have given answer in its term..
hc verma ki ebook nahin milti yaar....mere paas sachi mein hc verma nahin hai...........
arey e buk dhundle :P
waise bhi etre yahn koi tym pass ke liye kuch ni hai xcept 4 pool :P
chall hcverma ka gauss law wala topic dekh, udhar se diya hain e wala.
Good prblem[1]
Usphere=Interaction energy+Self energy
Here we consider a ring of radius r and width dr , so Self energy associated with it can be neglected.
=> dU=VsdQ
Here Vs =(4/3 Ï€r3Ï)/4πεr =Ïr/3ε
and dQ=ÏdV=Ï(4Ï€r2dr)
=>dU=4Ï€/3ε Ï2r4dr
Integrating with limits 0 to R
=>U=4Ï€Ï2/3ε R5/5
haan ni karnege mein kuch aur soch ri thi sorry
here d sol
energy=Vdq
=(4/3 Πx3)(4Πx2σdx)
isse int karne se m gettin
(3/20q^2)/ΠεR
tere ans mein Ï ka term kyun nahin hai????????mujhe to mera soln theek lagta hai...
hey mathie...........reply to kar diya kar.........bata ye theek hai naa???????[12][12]