1its consequence of gauss law on the gaussian surface just inside the outer sphere
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. The potential difference between the surface of the solid sphere and the outer surface of the hollow shell is V. If the shell is now given a charge of -3Q, the new potential difference between the two surfaces is?
a)V
b) 2V
c) 4V
d) -2V
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4 Answers
62This one is not very difficult.
What is the extra electric field inside the shell due to a charge on the shell? (Zero)
So there will be no chagne in the electric field inside the two spheres..
So the potential difference will remain the same..
1
1yes I also got the answer using that
but the explanation for this given in the book was: when negative charge is added to the outer sphere, the potential drops. but potential drops the same value for every point within the outer sphere, so net Pot. Diff. remains the same...
Its this explanation that i dont understand..can u explain this?
1see the thing is quite clear
watever extra charge is added it goes to outer part of sphere
so its not going to affect the field b/w the spheres !
so
if u give 1 Billion coloumbs of charge also the field between the two sphErEs will not chANGE