1-qx/(r2+x2)3/2 i think
1.Positive charge Q is distributed uniformly over a circular ring of radius R.A particle having mass m and a negetive charge q,is placed on its axis at a distance x from the centre.Find the force acting on the particle and its time period if it is released.(Assume x<<R)
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3 Answers
3this give electric field at distance x from the centre
now force =E*q
as x<<R so F=KQxR3
where K =1/4∩ε0
thus time period =2Π/ω
and ω u can calculate from force
i.e force constant k=KQR3
T=2Î √km
=2Î √(KQR3/m)
