EMF induced?

JEE Mains 2015 Help › Electricity and magnetism questions › EMF induced?

In the figure, there is a square of side 'l'.
Ends C and D are pulled with velocity u. Find the induced emf at the instance when angle ABD is Î¸. Magnetic field is into the plane of paper.

#Physics #Electricity and magnetism

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eureka123 ·2009-07-31 10:11:53

i think it should be ends B and D

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iitimcomin ·2009-07-31 19:50:27

e=(Lucos2@/2sin@)B

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iitimcomin ·2009-07-31 19:56:19

-d(phi)/dt = -B dA/dt = -B d(2*1/2(2Lcos@)(Lsin@))/dt

d(Lcos@)/dt = u => d@/dt = -u/Lsin@

B[L²cos2@/2(u/Lsin@)] = e(induced)

B[L²ucos2@/2Lsin@] = e

(Lucos2@/2sin@)B

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aposlil ·2009-08-01 05:46:07

Îµ_ind= -d(B2xy)/dt
= -d(2Bx√l²-x²)/dt
Differentiate and put dx/dt= u and x=lcosÎ¸

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EMF induced?

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