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A parallel plate capacitor of area A and seperation d is filled with two wedges of dielectric of constants K1 and K2. What is the equivalent capacitance?
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3 Answers
3DRAW ALL VERTICAL LINES BRO!!!!!!.........[trivial but gives u correct approach!!!!!]
methodology ...
1. take rightmost bottom side as origin and find the eqxn of the diagonal !!!!
2.this will help u find the height of the diaelecric with varyin x [y = d/a x] [a is side of plate]
3.divide into vertical lines with seperation dx ...
4. dC = edxa/([d/a x/k2] + [d- d/a x]/k1)
5. integrate frm 0 to a ................
