find Ceq..HCV

the charges on both 1μF capacitors will be same also the charges on both 3μF capacitors will also be same because if we attach the battery the opposite way ...i e exchange its terminals then too the charge has to be same ....you can also say that there is a symmetry out there(not sure about this one ) now we can apply loop laws we shall have V= Q₁ + Q₂/3 AND 15Q₁= 7Q₂AND so we have Q₁=7V/12 and Q₂= 5V/4 ( hope i am correct) C_eq=[ Q₁+Q₂]/V Giving us C_eq= 11/6μF
really sorry :(

I don't think i can make an equivalent circuit for this question ..i am not able to judge the points which are at the same potential ...even if we want to decide we'll have to go for charge distributions

use delta conversion formula

Ans is 11/6. :(

i dont know anything called delta star conversion..my sir told it is out of syllabus

shriyas diag. is fine. just check whether the eqns r correct.

Dont wory abt eq circuits. u wont get them that easily (frg8 delta star too) .. Just apply KVL for capacitor loops

ya i knew dat method.. HCV solved ex its done like that..its a bit long for complicated citcuits..so i was thinking if there is a better way.

i have corrected the mistake