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(x/2.R/x/2+R+R)||(R)=x
where || means 'is in parallel with'
** assuming
1. that RAB=RBC=RCA=R
2. x is the net resistance of circuit
find equivalent resistance across AB (the two points at the base of the outermost equilatral trianngle..)
hint: use principle of symmetry.
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12 Answers
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62Sky.. this question has 2 variations...
1) Each resistance is R
2) The resistance is proportional to the length of the wire!
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dun u guys think the points T1, T2 , T3 are equipotential points.. //
1arey every line is R means every sides of triangle has R or what ???
i mean, res of AB is R or resistance of AC is R where C is point of intersection of vertex 2nd largest triangle with AB ?????????
1It is a symmetry question
the circuit is symmetrical about the perpendicular line to AB so all the junctions can be removed along perpendicular,and now from A to mid point and C to mid point same potential drop,so inner network useless,now four resistances each of R/2 left,with equivalent R/2