1yaar koi complete solution de sakta hai....
the battery of volatge V=10 V .. three capacitors each of 3μF and 5 resistors each of 1Ω are aranged as shown in the fig.
arrangement is left for long time so that steady state is reached.
then:
1) charge on cap 1
2) charge on cap 2
3) charge on cap 3
4) voltage drop across cap 3.
-
UP 0 DOWN 0 0 33
33 Answers
1i think due to dc source....
more stupid ans???????????
no current thro capacitor....
1represtation,
reproduction,
repetition,
..
choose d best which matches.....
33current flows in red wire i=10/3
V across C2 =iR =10/3
q=CV =10/3*3=10
V across C1=10
q=3.10=30
V across C3=10-iR=20/3
q=cV=20
1heheh... :D
etar theke toh question er circuit ta easy laglo :P
sorry... but ... :'(
1wowwwwwwwwwww!! ki rakom bachchader mato bojhali :P
but ... thanx ......
1Ans :
1 ) Cap1 : 30 μF
2) Cap2 : 10 μF
3) Cap3 : 20 μF
4) 20/3 V
Correct hai ????
1hey .. sky.. waiting fr u fr a lon time........
do u ve d sol fr dis?????????
is kingh kahn rit?????(#2)
1please ..............
i need some good explanation....
@nishant bhaiya or manish bhaiya or kaymant sir ...
can i have any one of yours' replies....
any ''confident'' replies from students will also do...
1teek.......... ab mujhe chod dho.....
i ll try it later.....
really not in a state to solve dis.... ma eyes r droopin..
1kisne kahah yeh arey ni u make diagrm n c itz nt same
only d currnt tru caps is zero n it acts like open circuit in
1v is same at any point in d circuit?????????/
makin a mistake here...........
1arey c jsut chnge d cube type structure into a flat one itz easy
1take it as say V1 nw d currnt wich will pass thru will b same so get an equaktion in V and V1 R is 1 u noe so u get V1 a s 10/3
then for d first one itz simply (10-0)3
for second u get (20/3 -10/3) 3
for d third one u get
10-10/3 into 3
i mean apply loop law
1dats wat i m askin frm d beginnin......... i kno its easy after findin v.......
but how do u find v ?????????
1u find d volatge drop u get V as 10/3
so nw d drop across d 2 cap is 20/3 so chrge is 20
:)
1@sri..wat do u say now???/ flaw in d q???????
i think theres some trick dat we don get it........... srry not we , i
1@sky....There r two unneccessary wires conncting (note the sides of cuboid )...If u remove them and drw , i will b a simple linear circuit.......I think king is rite.....