flux ques

value of [flux]*[epsilon] through curved surface=?..

i'm getting 56/65..
pls confrm...

6 Answers

1
seoni ·

how ?
i did flux[curve]= q/E - flux thru 2 circles

flux thru 2 circles=q/2E[1-4/5], q/2E[1-12/13]....got this by integrating..

now subtract--- u get 56/65.,

1
seoni ·

pls check---3/5 ki jagah 4/5 aayega shayad,,same with 5/13

1
Ricky ·

Yep , I did a silly mistake . Your answer is absolutely correct . However , there is no need of doing painful integrations if you know the concept of Solid Angle .

1
seoni ·

i don't know much abt solid angle....how does dat helpt here? pls tell[in short]

thanks

1
Ricky ·

I have CBSE AISSCE Mathematics exam tomorrow : ) I ' ll start a long thread on the ways of calculating flux and about solid angles tomorrow only , okay ? Please wait for a day : )

1
seoni ·

thanks ricky---i too hav it--all d best..

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