Gauss's law

Q) A point charge q is placed at the origin. Calculate the electric flux through the open hemispherical surface :(x-a)^2+y^2+z^2=a^2 , x ≥ a.

3 Answers

24
eureka123 ·

http://targetiit.com/iit-jee-forum/posts/gauss-s-law-11256.html

1
Avinav Prakash ·

nishant bhaiya ..how to solve this without using solid angle?? plz help..

62
Lokesh Verma ·

it is solved without solid angle by the method as highlighted by kaymant sir, by taking the integral of E.ds over the surface..

ds is perpendicular to the surface while E is directed radially ...

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