googly from ATGS 13

last one for today!

suppose we are charging a capacitor of capacitance C across a potential difference(battery) of V.

Energy stored in capacitor = 12CV2

work done by battery=q.V

but q=CV
so work done = CV2.

where did the rest 50% energy vanish??

we can say that this is due to the energy loss due to i2R losses.

but suppose we use super-conductors and ideal batteries, so there is no R,

the equations still remain the same.

how do u now account for the loss in energy????

37 Answers

49
Subhomoy Bakshi ·

sir, let us think of the case when we sort the two ends of an ideal battery,

since practically no work is done in moving a charge from one terminal to the other, then they must be at same potential.

isn't it so??

then how can we conclude that batteries give constant potential difference??

1
hacker ·

@moy.....i feel like killing u u know??[13][13]

1
Shirsa Aich ·

Rath sir's question isnt it subhomoy?

49
Subhomoy Bakshi ·

not really :P

6
Kalyan IIT-K Beware I'm coming ·

subhomoy is choor!!
rath sir's question!!! i also thought of coming nd asking dis one nd get a pink post!!!

49
Subhomoy Bakshi ·

difference b/w u and me then is U THINK AND I DO!! :P

39
Pritish Chakraborty ·

The way you two fight over pink posts is almost like a bunch of 4-year old kids fighting for candy. How sweet indeed.
Now could someone please finish this question?

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