googly from ATGS 15

Let ' s look at the behaviour of the phenomena caused by the charge " q " placed in front of the conducting plane . First , it will induce some charges on the plane itself . Then , there would arise a mutual attraction , due to which the charge " q " will gain some potential energy . But , if we try to move away the charge , then the charge distribution of the induced charges will change . In fact , the charge distribution on the plane at a distance " x " from the foot of the perpendicular drawn from the charge " q " when it is at a distance " d " from the plane could be derived as -

σ = - q d2 Ï€ ( d ² + x ² ) ^{3 / 2}

Hence , if the charge distribution changes , then there would arise a field , which obviously will become time - dependant . So , it no longer will satisfy the concept of potential , as " Potential " could only exist in case of time invariant fields .

btw the question doesnt mention the word CONDUCTIONG PLATE at all [3]

kaymant sir can u explain it plzzz??????

yaar can neone plzz explain me image method with an example plzzzzzzzzzz????????????

The second process is correct . First of all , the charge placed will induce some charges on the plate , which in turn would create a field . But , the field caused by the induced charges is not a " Potential Field " . To make things sound more clear , it would be better if I say the integral of this field around a closed path is non - zero . That is why the concept of " Potential " fails here .

In other words , Work Done = Loss In Potential Energy

this relation will not be true in this case .

i know it i know it....eureka...:P:P