@kamalendu, with your correction taken into account and with a sign correction (in the last line in post #3, there should be a plus in front CE2), your solution is correct. The heat evolved turns out to be \dfrac{1}{2}C\mathcal{E}_2^2. Intersetingly, this heat generated does not depend on \mathcal{E}_1!!
What amount of heat will be generated in the circuit shown after the switch Sw is shifted from position 1 to position 2?
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arre but if the ans is 0.5CE22 then kahi na kahi to katega hi naa.....
can u pl. write the Final Equation
UI = 0.5C(E1-E2)2
UF = 0.5C E12
wer did CE1E2 term get cancelled?????///
REALLY ...I WAS VERY CASUAL IN SOLVING IT...BASH ME!! SO MANY SILLY ERRORS!!
initially wen switch 1 was closed,
charge in the capacitor = q1 = (ε1 - ε2)C
then, when switch 2 is closed,
charge in the capacitor = q2 = - Cε1
net charge flowing through ε1 = C(ε2 - 2ε1)
energy supplied by ε1 = heat produced in the circuit
= Cε1(ε2 - 2ε1)
ooops!! another mistake....sorry..W=CE1E2....Now I think I am right