33PE=-M.B
zero for (ii)
for (I) it is MB (max)
so (I)>(III)>(II)>(IV)
IV has negative PE
so answer is b
Figure represent four option of a current carrying coil in a magnetic field directed towards right.
a) I>II>III>IV
b) I>III>II>IV
c) II>III>I>IV
d) I>III>IV>II
Plz.... Gudie me guys....
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3 Answers
33
1U= -MB cos∂
= -iAB
U(I) = -iAB cos 180 = +AB
U(II) = -AB i cos 90 =0
U(III) = -AB cos 135 = -iAB/√2
U(IV) =-AB cos 45 = -iAB/√2
so ans : b) I>III>II>IV