24haan bhai..maine bhi element liya aur uspe variable torque likha or integrate kiya...par ans nahin aa raha
tera ans kya aa raha hai ??
9 Answers
1find the torque of E about z axis.....θ pe jaake dθ ka element cut karna aur uspe torque nikalke integrate karna..........
u din get method or ans not matching????
24
11.dF=E\lambda Rd\Theta cos\Theta
d\tau =\lambda R^{2}cos\Theta d\ThetaE
\tau =\int_{\Theta -\pi /2}^{\Theta }{}\lambda R^{2}cos\Theta d\ThetaE
MR2\alpha=\lambda R^{2}E(cos\theta +sin\theta )
\alpha=\lambda E(cos\theta +sin\theta )/m
1wdw/d\theta=\lambda E(cos\theta +sin\theta )/m
integrating both sides, using the condition w=0 at t=0,
w=\sqrt{2\lambda E(sin\theta -cos\theta -1)/m}
24haan yaar aise hi kiya.. par lower limit θ-π/2 kaise ??
koi clockwise ,anti clockwise ka chakkar hai kya ???
and btw ..ω=√2λE/m (cosθ+sinθ-1)
1acc. to ur ans, w=0, wen \Theta=0,
but shouldnt it hav some w at \Theta=0,[12]
1but at t=0, @=pi/2...after sometime, @ will be 0.So it will gain w.