Electricity and magnetism

1

Optimus Prime ·2009-04-02 09:12:04

is it 2R-2

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big looser ......... ·2009-04-02 09:20:15

ans is R[ (2k-1) + √4k²+1]/2k

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1

Optimus Prime ·2009-04-02 09:21:56

at first i was getting a long answer, can u give options?

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62

Lokesh Verma ·2009-04-02 09:25:49

solve this :

x = R + kxR/(kx+R)

can you see the logic?

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1

Optimus Prime ·2009-04-02 09:26:07

R[(2k-1) + √4k²+1]/2k

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big looser ......... ·2009-04-02 09:31:42

x = R + kxR/(kx+R)
how ????????????????????????

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vector ·2009-04-02 11:02:16

x= resistance b/w a n b n the resistance in next section is looking as if all d resistances ve been multiplied by k net resistance r kx

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big looser ......... ·2009-04-02 11:10:12

koi fayda nai, samajh ni ara

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62

Lokesh Verma ·2009-04-02 20:12:47

assume that the equivalent resistance is X

now take the new circuit

Its equivalent resistance will be kX

Now see that the old circuit is same as

Now you can solve it?

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