Just the basics:

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A Particle P has a mass of 10mg and a charge of -0.01 ÂµC. Each plate has a surface area 100cm² on one side. What potential difference V should be applied to the combination to hold the particle P in equilibrium?

#Physics #Electricity and magnetism

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Bicchuram Aveek ·2010-07-10 00:52:05

4.27 x 10^-3 V ?????

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venkateshan ·2010-07-10 08:32:53

How did you solve it...
can you plz tell me the equilibrium forces acting on the particle....

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ajoy abcd ·2010-07-10 09:34:27

mg=qE, where E=Ïƒ/2Î£_o.=q_c/A2Î£_o...
(q_cis charge on capacitor)
q_c=CV..find V

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Bicchuram Aveek ·2010-07-10 10:50:15

never a better explanation ... ;-)
anyways is the answer right ?

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

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Just the basics:

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