24how did u get that ???
14 Answers
3current in left and right circuits are 1A .........
eure it is shorted because the capacitor is full and it dosnt allow current to pass through it so potential in the left is -1V and in the right is -2V
(-1) - (-2) = 6+q/C or q = -5μC
SRY EDITED .. SILLY MISTAKE
-2 - (-1) = 6 + q/c
-7 = q/c
q = -7 μC
24hey sharman..part Cd is shorted becz Vc=Vd ...its connected by conducting wire....
and i dont think ans is 5 either.....asish told tha tans was 7 maybe..i dont remember exactly..
3cd is shortyed because its in steady state dude ...... capacitor is fully charged so acts like infinite ressistance ...
ans will be seven if the battery terminals are flipped...
3oh!!!! shit ...... ive made a mistake....
the potential in the left is -2 and that in the right is -1
so we have
-2 - (-1) = 6 + q/c
-7 = q/c
q = -7 μC
1at steady state;current through branch CD is 0.
applying kirchoffs 2.nd law in the loop CEDC;
6-q/1=0
so; q=6 uc.
1eureka seems right..the Vc = Vd so no current will flow through the capacitor..so no charge :))...so it will have zero resistance [not infinite becoz for getting charge the current has to pass]
3hey eure and rohit one thing u need to understand,if current is zero then it doesnt mean charge on the capacitor is zero.
dq/dt=0;q=c; okie.
dont get confused by taking c=0
1we integrate it from 0 tO Q with respect to time???n its not mentioned that the capacitor is initially charged..so cant we make that assumption???