Magnetic field question by eureka.

no takers?

THis one is simple!

μ₀(2I₀)2Ï€a

hmm.. this is a direct symmetry arguement...

Think of the 3I current as I + 2I

the I will get cancelled with the other 4 I currents

so we are left with 2I current in the lowermost wire..

Done :)

See there is a regular pentagon..

So if the question had 5 currents, each of value I₀, then by symmetry, the answer woudl be zero...

Here you have replaced one I by 3I in the lowermost wire..

Hence by superpositoin, it is the same as finding the magnetic field due to a single wire of current 2I