1oooo........... this is a solved eg in d buk perceptive physics :)
here u'll get 2 batteries bas baki sab aajayega i guess
i am not getting the solution. plzz try this.
A light conducting string, with one end fixed to the ceiling is wound to the rim of conducting ring of mass `m` and radius r with centre c.A uniform magnetic field B exists normal to tha plane. The string and conducting plane are connected at the top by resistance R. the ring is released at t=0.
a) draw a circuit diagram corresponding to the instant when the velocity aatained by the ring is v1.
b) draw the FBD of the ring at this instant.
c)Write down the equations relating to the translational and rotational motion of the ring and solve them to obtain the instantaneuos velocity.
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6 Answers
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39then please solve it na. i dont have that book whatever u said.
u r saying its simpe, atleast give me the diagram, plzz
1hey dear sorry i 2 dont hav dat buk had refered 2 it once in clases library
if i'll egt d sol i'll post :)
33
Emf of each arm =Bv2r
two cells are in parallel...(no resistance of circle given)
i=2Brv/R
Net force downward.. =mg-F-T
F' is magnetic force=(i/2)2rB.. on each semicircle...
so net F-2F' =2iRB=4B2r2v/R
a=g-4B2r2v/Rm-T/m...(i)
Tr=mr2α
a=αr
so a=T/m
now eq(i) becomes ..
a=g/2-2B2r2v/mR
dv/dt=g/2-2B2r2v/mR ..(diff equation..)solve it..limit 0->v, 0->t