pls explain....
On two smooth fixed parallel rod, a rod of mass m and kength l is placed. Ends of fixed rod is connected with battery and resistance and uniform magnetic field is present inside the page switch is closed at t=0.
A. when switched is closed rod will move in positive X- direction
B. rate of change of acceleration of rod will increase
C. acceleration of rod is constant
D. initial current in circuit is 0.
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UP 0 DOWN 0 0 5
5 Answers
Dr.House
·2009-02-15 06:48:20
this one is damn easy dude. E=BVL so i=BVL/R
now as F=BiL THEREFORE F=B2L2V/R
here V IS VELOCITY. now u proceed
Sunil Kumar
·2009-02-15 06:48:33
see At t=0, I = ξ/R
therefore F = I l B
then by using the Right hand rule u will find that rod moves in +ve X direction...
Got it..