And see my explanation there.....n pls tell me if i m correct
A wire of length l has current i
apply amperes law
∫B.dx=μi
B.2pir=μi
B=μi/2πr ...(:P same as of infinite wire.)
But we know it should be
B=μi(sinα+sinβ)/4πr
Explain what is wrong..
[3]
-
UP 0 DOWN 0 0 5
5 Answers
tapanmast Vora
·2009-04-06 09:49:38
is statement mein sayad
B.2pir=μi
coz u gotta select crrct amperian loop of uniform charg distrinuition effect to get gud results
Aditya
·2009-04-06 09:51:04
see this>>>http://targetiit.com/iit_jee_forum/posts/highly_conceptual_2457.html
Abhishek Priyam
·2009-04-06 09:54:11
opsie this was dioscussed..
But i think wrong post is pinked there.. post#3 is wrong
post#13 is correct