Multiple again

No a an ab are not connected acoording to the ques an its not one sorry

accha got it is it 3f???

For such problems, solve by numbering the plates as 1,2,3,4... this will avoid all sort of confusions... n u'll not commit any error (unless u do some silly mistake) !!!

for example, in d above problem numbering the plates can be done as 1,2,1,3 from top to bottom (first n third plate are given same no. as they are connected)

we need to find d net capacitance b/w A & B i.e., b/w 2 & 3

now, two capacitors exist between 1 and 2 and one capacitor exists between 1 and 3... first two capacitors are parallelly connected, so net capacitance will be 2C and this is connected in series to the third one... hence net capacitance = 2C/3...

therefore C_AB=2C/3 ........

dun laugh at me for such a detailed explanation... this is juzz for ur clear understanding so dat u can solve all such similar problems :)

Thanks a lot race......i needed the explanation too :)