11I'm not sure whether I'm correct or not.....
Consider a particle on 1 wall......the field on this due to the current is \frac{\mu_0 I }{2\pi.2r} So force = BIl, Thus pressure= \frac{Force}{Area}=\frac{\mu_0I^2l}{4\pi r.2\pi r.l}=\frac{\mu_0 I^2}{8\pi^2r^2}
Pls correct my mistake, if I'm wrong.
